35x^2-24x-7=0

Solution for 35x^2-24x-7=0 equation:

35x^2-24x-7=0

a = 35; b = -24; c = -7;
Δ = b2-4ac
Δ = -242-4·35·(-7)
Δ = 1556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1556}=\sqrt{4*389}=\sqrt{4}*\sqrt{389}=2\sqrt{389}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-2\sqrt{389}}{2*35}=\frac{24-2\sqrt{389}}{70}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+2\sqrt{389}}{2*35}=\frac{24+2\sqrt{389}}{70}
$